20x^(2/3)-6x^(1/3)-2=0

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Solution for 20x^(2/3)-6x^(1/3)-2=0 equation: 


x in (-oo:+oo)

20*x^(2/3)-(6*x^(1/3))-2 = 0

20*x^(2/3)-6*x^(1/3)-2 = 0

t_1 = x^(1/3)

20*t_1^2-6*t_1^1-2 = 0

20*t_1^2-6*t_1-2 = 0

DELTA = (-6)^2-(-2*4*20)

DELTA = 196

DELTA > 0

t_1 = (196^(1/2)+6)/(2*20) or t_1 = (6-196^(1/2))/(2*20)

t_1 = 1/2 or t_1 = -1/5

t_1 = -1/5

x^(1/3)+1/5 = 0

1*x^(1/3) = -1/5 // : 1

x^(1/3) = -1/5

( -1/5 < 0 i 1/3 in (0:1) ) => x naleu017Cy do O

t_1 = 1/2

x^(1/3)-1/2 = 0

1*x^(1/3) = 1/2 // : 1

x^(1/3) = 1/2

x^(1/3) = 1/2 // ^ 3

x = 1/8

x = 1/8

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